Am I crazy, or does 11pi/4 lie in quadrant 3?

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SUMMARY

The discussion centers on the position of the angle 11π/4 on the unit circle. It is confirmed that 11π/4 corresponds to the same position as 3π/4, which is located in quadrant 2. However, when considering the negative angle -11π/4, it indeed lies in quadrant 3. The confusion arises from misreading the original question, which specifically asked for the negative angle.

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LordofDirT
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Am I crazy, or does 11pi/4 lie in quadrant 3? That's what the back of my book says. But when I count it out on the unit circle it lands in quadrant 2 where 3pi/4 is located.
 
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11pi/4=2pi+3pi/4. So it lies in the same quadrant as 3pi/4. You aren't crazy.
 
Actually, I think I really am. The original question was asking for t = -11pi/4, which would put me at quadrant 3.

Thanks
 
Well, at least you know how to do the problem. Now you just have to learn to read it correctly.
 

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