MHB Am I doing this related rates right?

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The discussion centers on solving a related rates problem involving a potter shaping clay into a cylinder, where the height is increasing and the radius is decreasing. The user derived the formula for the rate of change of the radius using the volume of the cylinder and differentiated it correctly. They calculated the rate of change of the radius to be approximately -0.0107 cm/sec when the radius is 1.5 cm and height is 7 cm. Another participant confirmed the calculation and pointed out a simplification of the formula. The overall consensus is that the user's approach and answer are correct.
TheFallen018
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Hey guys,

I have this related rates problem that I'm working through. I think I might have an answer, but I'm not sure.

Here's the question.
A potter shapes a lump of clay into a cylinder using a pottery wheel.
As it spins, it becomes taller and thinner, so the height, h, is increas-
ing and the radius, r, is decreasing. If the height of the cylinder is
increasing at 0.1 cm per second, find the rate at which the radius is
changing when the radius is 1.5cm and the length is 7cm.


I used the volume of the cylinder for this, and attempted to differentiate it. I ended up with this:

$\frac{d}{dt}V=\frac{d}{dt}(\pi{r}^{2}(t)h(t))$

$0=\pi(2r\frac{dr}{dt}h+\frac{dh}{dt}{r}^{2})$

Which broke down to:

$\frac{dr}{dt}=-\frac{h'{r}^{2}}{2rh}$

Which came out as approximately -0.0107 cm/sec

Does this look about right, or have I gone horribly wrong?

Thanks :)
 
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Looks good. I got the same answer.
 
I feel an overwhelming need to point out that \frac{-h'r^2}{2rh}= \frac{-h'r}{2h}.
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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