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IntegrateMe

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Write an integral expressing the amount of force on one trapezoidal side of the vessel when the height of the water is H meters. The density of rainwater is 1000 kg/m

^{3}and the force of gravity is 9.8 N/kg.

The solution says:

F = δ*g*depth*A

depth = (H-h)

A = (1+h)ΔH

And so F = ∫1000(9.8)(H-h)(1+h)dh ; from 0 to H

I don't understand how they got (H-h) to be the depth nor how the area = (1+h)ΔH. Anyone care to explain?

Thank you!