Amount of heat = 80 kJ -- how much ice can you melt?

  • Thread starter Thread starter Yeahaight
  • Start date Start date
  • Tags Tags
    Heat Ice
Click For Summary
SUMMARY

The discussion centers on calculating the mass of ice that can be melted using 80 kJ of heat. Participants clarify the use of the formula Q = mcΔT, emphasizing the need to consider the specific heat capacities of ice and water. The process involves three steps: heating the ice to 0°C, melting the ice, and then heating the resulting water to the final temperature. The key takeaway is that the total heat required can be expressed in terms of mass, allowing for the calculation of how much ice can be melted given the available heat.

PREREQUISITES
  • Understanding of the heat transfer formula Q = mcΔT
  • Knowledge of specific heat capacities for ice and water
  • Basic algebra for manipulating equations
  • Concept of phase changes in thermodynamics
NEXT STEPS
  • Calculate the specific heat capacity of ice and water for practical applications
  • Learn about phase change calculations in thermodynamics
  • Explore the implications of heat transfer in real-world scenarios
  • Study the relationship between heat, mass, and temperature changes in different materials
USEFUL FOR

Students in physics or chemistry, educators teaching thermodynamics, and anyone involved in calorimetry or heat transfer calculations.

Yeahaight
Messages
10
Reaction score
0
Homework Statement
How much ice at a temperature of -10°C can be melted and the resulting water heated to 20°C using 80 kJ of heat?
Given values:
t1 = 10°C
t2 = 20°C
Q = 80kJ
specific heat of fusion = 3,34*10^5 J/kg
c of ice = 2,2*10^3 J/kg * K
c of water = 4,2*10^3 J/kg * K
Relevant Equations
Q = cm(t2-t1)=cmΔt
I've been messing with the Q = cm(t2-t1)=cmΔt formula
If I change it to m=Q/(c*Δt) everything is fine until I reach the c part, because there has been given the c of ice and the c of water too, do I just subtract c ice from c water?
 
Physics news on Phys.org
Yeahaight said:
How much ice at a temperature of 10°C
Did you miss a minus sign there?
 
  • Like
Likes   Reactions: Yeahaight and etotheipi
jbriggs444 said:
Did you miss a minus sign there?
Yes, I did, sorry.
 
So solve the problem in steps. Heat the ice until it is at melting temperature. Melt the ice. Then heat the resulting water until it is at the final temperature.
 
  • Like
Likes   Reactions: Yeahaight
jbriggs444 said:
So solve the problem in steps. Heat the ice until it is at melting temperature. Melt the ice. Then heat the resulting water until it is at the final temperature.
Well, how do I do that if the mass of the ice isn't given?
 
Yeahaight said:
Well, how do I do that if the mass of the ice isn't given?

That's what you're trying to find. Call it ##m## and come up with an algebraic expression!
 
  • Like
Likes   Reactions: Yeahaight and jbriggs444
jbriggs444 said:
So solve the problem in steps. Heat the ice until it is at melting temperature. Melt the ice. Then heat the resulting water until it is at the final temperature.
So, the formula would be m=m1+m2?
 
Yeahaight said:
So, the formula would be m=m1+m2?

I'm not quite sure what that means. How much heat is required to heat a mass ##m## of ice from ##-10## degrees to ##0## degrees? How much heat is required to melt a mass ##m## of ice? How much heat is required to heat a mass ##m## of ice from ##0## degrees to ##20## degrees? What is the total amount of heat required, in terms of ##m##?
 
  • Like
Likes   Reactions: Yeahaight
etotheipi said:
I'm not quite sure what that means. How much heat is required to heat a mass ##m## of ice from ##-10## degrees to ##0## degrees? How much heat is required to melt a mass ##m## of ice? How much heat is required to heat a mass ##m## of ice from ##0## degrees to ##20## degrees? What is the total amount of heat required, in terms of ##m##?
So, basically my plan was -
Find the total amount of mass by changing the formulas up a bit, because every heat formula has a m in it. So I thought about changing the formulas so I find the m because I already have the other values given.
I thought about doing every step jbriggs said but changing the formulas required for the step, so I find the mass not the heat, because the heat is already given and when I do that, I just count up every mass - m1, m2
 
  • #10
For now, treat the 3 stages separately. In the relevant equations section you included ##Q = mc\Delta T##. With that in mind, how much heat (##Q##) is required to raise a mass ##m## of ice, with ##c = c_{ice}##, by ##10## degrees?

Can you do the same for the heating of water from ##0## degrees to ##20## degrees?
 
Last edited by a moderator:
  • Like
Likes   Reactions: Yeahaight
  • #11
Suppose you had 1 kg of ice. How much heat would it take to first raise its temperature to 0 C, then melt it, and then raise the temperature of the resulting water to 20 C?
 
  • Like
Likes   Reactions: Lnewqban and Yeahaight
  • #12
Chestermiller said:
Suppose you had 1 kg of ice. How much heat would it take to first raise its temperature to 0 C, then melt it, and then raise the temperature of the resulting water to 20 C?
When I have done that, how do I calculate the mass?
 
  • #13
Yeahaight said:
So, the formula would be m=m1+m2?
Are you not seeing that the all of the ice turns into water and the mass does not change? There is only one m.
 
  • #14
hutchphd said:
Are you not seeing that the all of the ice turns into water and the mass does not change? There is only one m.
Yeah, I figured that out already. The problem right now is how do I calculate the mass, if I know the total amount of heat.
 
  • #15
Yeahaight said:
Yeah, I figured that out already. The problem right now is how do I calculate the mass, if I know the total amount of heat.
@Chestermiller gave you all you need.

You can figure how much heat to deal with 1 kg.
You know how much heat you have.
So how many kg can you deal with, given that much heat?
 
  • Like
Likes   Reactions: Yeahaight
  • #16
Yeahaight said:
When I have done that, how do I calculate the mass?
You got to be kidding. If you have $1.00 dollar, and each item costs 20 cents ($0.20), how many items can you buy?
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
656
  • · Replies 17 ·
Replies
17
Views
6K
Replies
11
Views
2K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
25
Views
1K