Amount of moles emitted by burning oil

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Discussion Overview

The discussion revolves around calculating the number of moles of CO2 emitted from burning oil, based on global energy consumption figures. Participants explore the chemistry involved in the combustion of oil, including the stoichiometry of the reactions and the conversion of energy consumption into mass and moles of CO2 produced.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states the need to calculate how many grams/moles of CO2 are emitted by burning 1kg of oil, given that 1kg of oil yields 42MJ.
  • Another participant suggests writing a balanced reaction equation for the combustion of the CH2 groups in oil.
  • A different perspective asks for the mass of carbon and hydrogen in 1 kg of the oil, assuming the formula is CH2.
  • A participant proposes a balanced reaction equation and calculates the number of moles of oil and CO2 produced, questioning the correctness of their calculations.
  • One participant comments on the distinction between energy consumption and power, suggesting that the wording of the problem could be clearer.

Areas of Agreement / Disagreement

Participants generally agree on the chemistry involved in the combustion of oil, but there is some uncertainty regarding the interpretation of the energy consumption figure (16TW) and its implications for the calculations.

Contextual Notes

There are unresolved assumptions regarding the interpretation of energy consumption versus power, and the calculations depend on the accuracy of the chemical formula used for oil.

Donna14
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Homework Statement



Calculate the number of moles of CO2 that are emitted into the atmosphere per year due to the total energy consumption on Earth (16TW). Note: 1kg oil yields 42MJ and for oil C:H ' 1:2.

I don't know how to calculate how many grams/moles of CO2 are emitted by burning 1kg of the oil

Homework Equations



The Attempt at a Solution



- 1 mole CO2 is 44g

- I calculated that 1,22x10^13 kg oil is needed to cover the 16TW
 
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The problem approximates the formula for oil as a chain of CH2s. Each CH2 reacts with O2 to produce H2O and CO2. Can you write a balanced reaction equation for the reaction of each CH2 group with O2?
 
Or, from a slightly different (but yielding the same answer) angle: if the experimental formula is CH2, how many grams of C and how many grams of H in 1 kg of the substance?
 
Thank you so much for your input!

Let's check if I understand it better now:

2CH2+ 3O2 gives 2H2O + 2CO2

So 2 mol oil gives 2 mol CO2

1 mol oil weights 14g
1 mol CO2 weights 44g
1.22 x 1013 kg oil/ 14 x 10-3 = 871x106mol oil
Which equals the amount of moles CO2

Is this correct?
 
Chemistry looks OK to me, but on the second read I am not sure how to understand

Donna14 said:
due to the total energy consumption on Earth (16TW)

16TW is not energy consumption, it is power required. I see you assumed it is intended to mean "average power required throughout the year" - looks OK to me, still, question could be worded better.
 

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