Ampere's Law and Magnetic Fields

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SUMMARY

The discussion centers on applying Ampere's Law to a physics problem involving a zero-resistance rod sliding on rails in a magnetic field. The key calculations include determining the force required to maintain a constant current of 0.125 A through a 10.9-Ω resistor connected to the rails, using the formula F = I x B x length. The calculated force is 0.05 N, although the user suspects a unit error. Additionally, the rate of energy dissipation in the resistor can be calculated using P = I² x R, and the mechanical power delivered to the rod is found using P = F x velocity.

PREREQUISITES
  • Understanding of Ampere's Law and magnetic fields
  • Familiarity with Ohm's Law and power calculations
  • Knowledge of SI units, particularly Tesla (T) for magnetic field strength
  • Basic principles of electromagnetism and circuit analysis
NEXT STEPS
  • Study the derivation and applications of Ampere's Law in electromagnetic systems
  • Learn about the relationship between current, resistance, and power in electrical circuits
  • Explore the concept of mechanical power in the context of electromagnetic systems
  • Investigate the effects of varying magnetic fields on induced currents and forces
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the practical applications of Ampere's Law in electrical engineering and circuit design.

zzyzz
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Homework Statement



The figure shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 0.53 m. The rails are connected by a 10.9-Ω resistor, and the entire system is in a uniform magnetic field with a magnitude of 0.750 T.

23-33.gif


(a) Find the force that must be exerted on the rod to maintain a constant current of 0.125 A in the resistor.

(b) What is the rate of energy dissipation in the resistor?

(c) What is the mechanical power delivered to the rod?

Homework Equations



a.) F=I x B x length
b.) P=I^2 x R
c.) P= F x velocity

The Attempt at a Solution



This sort of problem has not been covered in lecture yet and I am having difficulties with it. I found these formulas in the book and I think they apply for these situations but I am not sure. For part A of the problem I tried plugging in .125A for the current, .53m for the length, and .750T for the magnitude. Which gave me F=(.125)(.750)(.53)=.05 . This answer is off by a multiple of 10. I'm assuming my mistake is with the units of B because I have not worked with this before. Any help would be appreciated, thanks
 
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Hi, zzyzz. Your work looks correct to me. Be sure to include the proper unit for the force. Tesla (T) is the SI unit for B, so there is no need to do any unit conversion. The only way that I can see that your answer would be wrong is if you misread a number given in the problem.
 

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