Ampere's Law and straight wires

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SUMMARY

The discussion focuses on calculating the magnetic field at specific points along the y-axis due to two parallel straight wires carrying a current of 19 A in the -x direction. The magnetic field formula used is B = (μ₀I)/(2πr), where μ₀ is the permeability of free space. The user initially calculated the magnetic field at y = -3.7 cm incorrectly, arriving at -0.12602 T. After receiving feedback, the user identified an error in their calculations and sought further assistance.

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  • Understanding of Ampere's Law
  • Familiarity with magnetic field calculations
  • Knowledge of the permeability of free space (μ₀)
  • Basic algebra for solving equations
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The figure below shows two long, straight wires in the xy plane and parallel to the x axis. One wire is at y = −6.0 cm and the other wire is at y = +6.0 cm. The current in each wire is 19 A. If the currents are both in the −x direction, find the magnetic field at the following points on the y axis.

http://www.webassign.net/tipler6/27-p-025.gif

(a) y = −3.7 cm

BL=(mu_o)I
B=[(mu_o)I]/2pi*r

-{(mu_o)I/2pi(distance-point)}+{(mu_o)I/2pi(distance+point)}, so the answer should be negative

My answer is somewhere around -.12602 T, which is wrong. Please help!
 
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