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- Homework Statement
- A spring is attached to the roof of an elevator and a mass m is attached to the lower end of the spring. When the elevator is not moving, the mass undergoes a vertical SHM with frequency 2.5rad/s. Now, when the elevator is moving downwards with velocity 0.5m/s, the mass is not undergoing any SHM. Now, if the elevator suddenly stops, what will be the amplitude of oscillation of the mass m?

- Relevant Equations
- y = ACosωt + BSinωt

From the first part of the question, I was able to get the value of ω which will be the same for the next SHM.

But, I am having difficulties solving for the amplitude as I can't find the boundary conditions required to get the amplitude.

But, I am having difficulties solving for the amplitude as I can't find the boundary conditions required to get the amplitude.

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