An accelerating sphere with a particle on it

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SUMMARY

The discussion focuses on the dynamics of a particle sliding off a smooth sphere of radius 'R' that is accelerating in a straight line with a constant acceleration 'a'. The derived formula for the speed of the particle with respect to the sphere as it slides down is given by v = √{2R[a sin(θ) + g - g cos(θ)]}. This equation incorporates gravitational acceleration 'g' and the angle 'θ' at which the particle descends, providing a clear relationship between these variables.

PREREQUISITES
  • Understanding of classical mechanics, specifically dynamics of particles.
  • Familiarity with the concepts of acceleration and gravitational forces.
  • Knowledge of trigonometric functions and their application in physics.
  • Basic proficiency in using LaTeX for mathematical expressions.
NEXT STEPS
  • Explore the implications of varying the angle 'θ' on the particle's speed.
  • Investigate the effects of different values of acceleration 'a' on the motion of the particle.
  • Learn about the conservation of energy principles in relation to the particle's motion on the sphere.
  • Study the application of similar problems in advanced dynamics and physics simulations.
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Physics students, educators, and professionals interested in classical mechanics, particularly those studying motion on curved surfaces and the effects of acceleration on particle dynamics.

randommanonea
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A smooth sphere of radius 'R' is made to translate in a straight line with a constant acceleration 'a'. A particle kept on the top of the sphere is released from there at zero velocity with respect to sphere. Find the speed of the particle with respect to the sphere as a function of the angle 'theta' it slides.
 
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Show us your work/attempt (as per PF rules).
 
OK Thanks, I got it.

Answer is v= {2R[a sin(theta) +g -g cos(theta)]}^{1/2}
PS: Testing Latex

v= \sqrt{2R[a \sin \theta +g -g \cos \theta]}
 

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