- #1
jcap
- 170
- 12
I start with the spatially flat FRW metric in conformal co-ordinates:
$$ds^2=a^2(\eta)(d\eta^2-dx^2-dy^2-dz^2)$$
This metric has the following non-zero Christoffel symbols:
\begin{eqnarray*}
\Gamma^0_{\alpha \beta} &=& \frac{\dot{a}}{a} \delta_{\alpha \beta} \\
\Gamma^i_{0j} &=& \Gamma^i_{j0} = \frac{\dot{a}}{a} \delta^i_j
\end{eqnarray*}
where ##\alpha,\beta=\{0,1,2,3\}## and ##i,j=\{1,2,3\}##.
Let us assume the following:
1. A massive particle travels on a geodesic ##x^\mu(\lambda)## with tangent vector ##U^\mu=dx^\mu/d\lambda## where ##U^\mu U_\mu=1##.
2. The 4-momentum of the particle is given by ##P^\mu = m U^\mu##.
3. A timelike vector field (not assumed to be a Killing field) ##\eta^\mu=\delta^\mu_0##, ##\eta_\mu=\eta^\nu g_{\mu\nu}=\delta^\nu_0g_{\mu\nu}=g_{\mu0}##.
The energy of the particle, ##E##, with respect to the co-ordinate system is given by:
$$E=\eta_\mu P^\mu=m\eta_\mu U^\mu$$
As the vector ##\eta^\mu## is not assumed to be a Killing vector then the energy ##E## is not necessarily constant.
Now the rate of change of the energy ##E## along the worldline ##x^\mu(\lambda)## is given by:
\begin{eqnarray*}
U^\nu \nabla_\nu(m\eta_\mu U^\mu)&=& mU^\nu U^\mu \nabla_\nu \eta_\mu + m\eta_\mu U^\nu \nabla_\nu U^\mu \\
&=& mU^\nu U^\mu \nabla_\nu \eta_\mu
\end{eqnarray*}
where the last term on the right-hand side is zero as the particle moves on a geodesic.
We now evaluate the covariant derivative in the above equation using ##\eta_\mu=g_{\mu0}##:
\begin{eqnarray*}
\nabla_\nu \eta_\mu &=& \partial_\nu \eta_\mu - \Gamma^\lambda_{\nu \mu} \eta_\lambda \\
&=& \partial_\nu g_{\mu0} - \Gamma^0_{\nu\mu} g_{00} \\
&=& \partial_\nu g_{\mu0} - \frac{\dot{a}}{a} \delta_{\nu\mu} g_{00} \\
&=& \mbox{diag}(a \dot{a},-a\dot{a},-a\dot{a},-a\dot{a}) \\
&=& \frac{\dot{a}}{a}g_{\nu\mu}
\end{eqnarray*}
Thus the rate of change of the energy of the particle along the geodesic is given by:
\begin{eqnarray*}
U^\nu \nabla_\nu(m\eta_\mu U^\mu) &=& m\frac{\dot{a}}{a}U^\nu U^\mu g_{\nu\mu}\\
&=& m\frac{\dot{a}}{a} \\
&=& m \frac{(da/d\tau)(d\tau/d\eta)}{a} \\
&=& m \frac{da}{d\tau}
\end{eqnarray*}
If I integrate both sides of the above equation I find that the energy ##E##, with respect to the metric co-ordinates, of any massive particle in geodesic motion is given by:
\begin{eqnarray*}
E = m\eta_\mu U^\mu &=& \eta_\mu P^\mu \\
&=& \eta^\mu P_\mu \\
&=& \delta^\mu_0 P_\mu \\
&=& P_0 \\
&=& ma
\end{eqnarray*}
Now let us calculate the energy ##E_{obs}## that a co-moving observer with 4-velocity ##U^\mu_{obs}=\frac{1}{a}\delta^\mu_0## measures when he observes the massive particle.
\begin{eqnarray*}
E_{obs} &=& U^\mu_{obs} P_\mu \\
&=& \frac{1}{a}\delta^\mu_0 P_\mu \\
&=& \frac{1}{a} P_0 \\
&=& \frac{1}{a} m a \\
&=& m
\end{eqnarray*}
Notice that the energy ##E_{obs}##, that a co-moving observer measures, is constant for any massive particle moving along a geodesic and not just constant for a particle that is at rest in the co-moving frame.
Therefore it seems that massive particles do not redshift as they travel on geodesics through the expanding Universe which is contrary to received wisdom.
Where have I gone wrong?
$$ds^2=a^2(\eta)(d\eta^2-dx^2-dy^2-dz^2)$$
This metric has the following non-zero Christoffel symbols:
\begin{eqnarray*}
\Gamma^0_{\alpha \beta} &=& \frac{\dot{a}}{a} \delta_{\alpha \beta} \\
\Gamma^i_{0j} &=& \Gamma^i_{j0} = \frac{\dot{a}}{a} \delta^i_j
\end{eqnarray*}
where ##\alpha,\beta=\{0,1,2,3\}## and ##i,j=\{1,2,3\}##.
Let us assume the following:
1. A massive particle travels on a geodesic ##x^\mu(\lambda)## with tangent vector ##U^\mu=dx^\mu/d\lambda## where ##U^\mu U_\mu=1##.
2. The 4-momentum of the particle is given by ##P^\mu = m U^\mu##.
3. A timelike vector field (not assumed to be a Killing field) ##\eta^\mu=\delta^\mu_0##, ##\eta_\mu=\eta^\nu g_{\mu\nu}=\delta^\nu_0g_{\mu\nu}=g_{\mu0}##.
The energy of the particle, ##E##, with respect to the co-ordinate system is given by:
$$E=\eta_\mu P^\mu=m\eta_\mu U^\mu$$
As the vector ##\eta^\mu## is not assumed to be a Killing vector then the energy ##E## is not necessarily constant.
Now the rate of change of the energy ##E## along the worldline ##x^\mu(\lambda)## is given by:
\begin{eqnarray*}
U^\nu \nabla_\nu(m\eta_\mu U^\mu)&=& mU^\nu U^\mu \nabla_\nu \eta_\mu + m\eta_\mu U^\nu \nabla_\nu U^\mu \\
&=& mU^\nu U^\mu \nabla_\nu \eta_\mu
\end{eqnarray*}
where the last term on the right-hand side is zero as the particle moves on a geodesic.
We now evaluate the covariant derivative in the above equation using ##\eta_\mu=g_{\mu0}##:
\begin{eqnarray*}
\nabla_\nu \eta_\mu &=& \partial_\nu \eta_\mu - \Gamma^\lambda_{\nu \mu} \eta_\lambda \\
&=& \partial_\nu g_{\mu0} - \Gamma^0_{\nu\mu} g_{00} \\
&=& \partial_\nu g_{\mu0} - \frac{\dot{a}}{a} \delta_{\nu\mu} g_{00} \\
&=& \mbox{diag}(a \dot{a},-a\dot{a},-a\dot{a},-a\dot{a}) \\
&=& \frac{\dot{a}}{a}g_{\nu\mu}
\end{eqnarray*}
Thus the rate of change of the energy of the particle along the geodesic is given by:
\begin{eqnarray*}
U^\nu \nabla_\nu(m\eta_\mu U^\mu) &=& m\frac{\dot{a}}{a}U^\nu U^\mu g_{\nu\mu}\\
&=& m\frac{\dot{a}}{a} \\
&=& m \frac{(da/d\tau)(d\tau/d\eta)}{a} \\
&=& m \frac{da}{d\tau}
\end{eqnarray*}
If I integrate both sides of the above equation I find that the energy ##E##, with respect to the metric co-ordinates, of any massive particle in geodesic motion is given by:
\begin{eqnarray*}
E = m\eta_\mu U^\mu &=& \eta_\mu P^\mu \\
&=& \eta^\mu P_\mu \\
&=& \delta^\mu_0 P_\mu \\
&=& P_0 \\
&=& ma
\end{eqnarray*}
Now let us calculate the energy ##E_{obs}## that a co-moving observer with 4-velocity ##U^\mu_{obs}=\frac{1}{a}\delta^\mu_0## measures when he observes the massive particle.
\begin{eqnarray*}
E_{obs} &=& U^\mu_{obs} P_\mu \\
&=& \frac{1}{a}\delta^\mu_0 P_\mu \\
&=& \frac{1}{a} P_0 \\
&=& \frac{1}{a} m a \\
&=& m
\end{eqnarray*}
Notice that the energy ##E_{obs}##, that a co-moving observer measures, is constant for any massive particle moving along a geodesic and not just constant for a particle that is at rest in the co-moving frame.
Therefore it seems that massive particles do not redshift as they travel on geodesics through the expanding Universe which is contrary to received wisdom.
Where have I gone wrong?