An elusive trig proof I can't seem to get

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Homework Help Overview

The problem involves proving a trigonometric identity: (sin(x) + tan(x)) / (cos(x) + 1) = tan(x). The subject area is trigonometry, focusing on identities and algebraic manipulation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the validity of the original equation and clarify the intended expression. There are attempts to manipulate the equation algebraically, including multiplying both sides by cos(x) and factoring.

Discussion Status

The discussion is ongoing, with participants providing guidance on algebraic manipulation and clarifying the original statement of the problem. Multiple interpretations of the equation are being explored.

Contextual Notes

There is a noted mistake in the original equation as presented by the original poster, which has led to some confusion in the discussion. Participants are addressing this misunderstanding while attempting to guide towards a proof.

SpecialKM
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Homework Statement



Prove that:

(sin(x)+ tan(x))/(cos(x)+ 1)= tan(x)

Homework Equations



There are just trig identities that we can use.

The Attempt at a Solution


I've attempted every possible way I can think of and it would just look like jibberish here.
 
Last edited:
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What you wrote, sin(x)+ tan(x)/cos(x)+ 1= tan(x). isn't true! For example, if x= 0, then sin(x)= sin(0)= 0, tan(x)/cos(x)= tan(0)/cos(0)= 0/1= 0 so the left side is 1. But the right side, tan(x)= tan(0), is 0.

What I think you meant was (sin(x)+ tan(x))/(cos(x)+ 1)= tan(x).

If you multiply both sides of the equation by cos(x) you get
(sin(x)cos(x)+ sin(x))/(cos(x)+ 1)= sin(x).
 
Sorry yeah, that's what I meant, my mistake. I'll change that right now.
 
Use the fact that tan(x)=sin(x)/cos(x). The proof should just involve two lines of algebra.
 
factor out tan(x) from numerator and u get cos(x)+1 which cancels with denominator
 

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