An intro to real analysis question. eazy?

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SUMMARY

The discussion focuses on proving that if a function g satisfies the conditions f(g(x)) = x for all x in B and g(f(x)) = x for all x in A, then g must be the inverse of the bijection f, denoted as f^-1. The key argument is that since f is a bijection, it has a unique inverse, and g fulfills the criteria that define this inverse. Therefore, g is conclusively shown to be equal to f^-1, establishing its uniqueness as the inverse function.

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  • Knowledge of inverse functions
  • Basic principles of real analysis
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Homework Statement



Let f : A -> B be a bijection. Show that if a function g is such that f(g(x)) = x for
all x ϵ B and g(f(x)) = x for all x ϵ A, then g = f^-1. Use only the definition of a
function and the definition of the inverse of a function.


Homework Equations





The Attempt at a Solution


well since f is a bijection then there exist an f^-1 that remaps f back to A and since g does that then g is the unique inverse of f, or something like that please help I am not very good that this stuff
 
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Yes, you only need to prove uniqueness of an inverse function. If f(g(x))=x, then g(x) must be the unique argument a for which f(a) = x. And so, this condition completely defines g for all the arguments. g is then obviously equal to f-1.
 
thanks losiu for your response.
but how do you prove that it is the unique inverse?
 

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