Analysis of the Isospin of meson and baryon bounded states (particle physics)

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SUMMARY

The discussion focuses on the isospin states of various meson and baryon combinations, specifically addressing the conditions under which these combinations can exist with isospin I=1. The user correctly identifies that combinations such as \(\pi^0\pi^0\), \(\pi^+\pi^-\), and \(\Sigma^0\pi^0\) can exist in this state, while combinations involving the \(\Lambda^0\) baryon yield different results due to its I=0. The user realizes the importance of conservation laws in determining the possible isospin states and concludes that all combinations are possible under certain conditions, correcting their initial misunderstanding regarding the conservation of spin.

PREREQUISITES
  • Understanding of isospin and its conservation in particle physics
  • Familiarity with angular momentum addition rules
  • Knowledge of specific particles' isospin values, such as pions and baryons
  • Basic concepts of Clebsch-Gordan coefficients for angular momentum coupling
NEXT STEPS
  • Study the conservation of isospin in particle interactions
  • Learn about Clebsch-Gordan coefficients and their application in quantum mechanics
  • Explore the implications of isospin in the context of the Standard Model of particle physics
  • Review examples of isospin coupling in meson and baryon systems
USEFUL FOR

This discussion is beneficial for students and researchers in particle physics, particularly those focusing on meson and baryon interactions, isospin conservation, and angular momentum theory.

jonjacson
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Homework Statement



Part A)

Establish which of the following combinations of particles can exist in a state of I=1 :

a) \pi^0\pi^0
b) \pi^+\pi^-
c) \pi^+\pi^+
d) \Sigma^0\pi^0
e) \Lambda^0\pi^0

Part B) of the problem is:

In what states of isospin may exist the following systems?

f) \pi^+\pi^-\pi^0

g) \pi^0\pi^0\pi^0

Homework Equations



Conservation of the Isospin.

Addition rules of angular momenta (the same rules of the Isospin)

The Attempt at a Solution



Well I have searched which are the values of the Isospin of the particles, and this is what i have found:

- I=1 for the pions

- I=1 for the sigma barion

- I=0 for the lambda baryon

Using the addition rules of the angular momenta in every case give me this result:

J = j1+j2 , j1+j2-1, j1+j2-2 ... /j1-j2/ ; in the case of j1 > j2

a) I=1, I=1, so the total Isospin of the coupled state could be I=2,1,0 , and this three states of total Isospin are including 1 of the statement, so this combination can exist.

b) c) d) are the same case of the a).

e) Now we have I=0 for the lambda baryon and I=1 for the pion so:

Total I= 1, 0 and the state is posible again because I=1 is a posible value. It is very strange that the first statement of the problem talks about "which of the following..." in singular, but ¿does it mean that there is only one answer?.

Surprisingly i have found that all the states are possible, and this is worrying me.

For the part B) we have:

f)

\pi^+\pi^-\pi^0 , all of them have I=1 , I have used the results of part A) and then i have added the Isospin of the third particle.

So for the \pi^+\pi^- , I have I= 2, 1 ,0 , let's analyze the three cases:

I=2, the pi0 isospin is I=1 so : I total= 3,2,1

I=1, and I=1 so I total=2,1,0

I=0, and I=1 so I total = 1, 0

But the Isospin must be conserved, so the only possibility is I total = 3.

¿is this right?g)

If i am not wrong is the same case as f) .

But this looks very strange, i don't understand why there are a lot of parts similar, I am almost convinced that i am doing something wrong.

¿have I applied correctly the theory of the angular momentum? ¿Should I calculate the eigenstates, eigenvalues... with clebsh gordan coefficients?.

I have to send some problems (one of them is the one of this thread) to my teacher and it will be the 15 % of the value of the exam, so it is very important for me, if I am rigth ¿Could somebody confirm it?.

Thanks.
 
Last edited:
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Now i understand the mistake in part A) I had forgotten conservation of the spin in a)b)c)d) , these combinations can only have I=2 due to conservation, and the correct answer of the problem is part e) .

It's much more logical.

¿What do you think?.
 
Hello Is there anybody here?
 
There aren't answers in this thread ¿Can anybody explain to me why? . I think that I have followed the rules of the forum, perhaps I am doing something wrong ¿Could you tell me what it is?.

Thanks in advance, I am very sorry for this.
 

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