Analysis Problem, limits & supremum, infimum and sequences

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SUMMARY

The discussion centers on proving the inequality liminf(sn + tn) ≥ liminfsn + liminftn for bounded sequences (sn) and (tn) in R. The user successfully derived this result by applying properties of limits, specifically using the relationship lim infSn = -lim sup(-Sn) and manipulating inequalities involving lim sup. The conclusion emphasizes the importance of understanding the behavior of sequences and their limits in analysis.

PREREQUISITES
  • Understanding of sequences in real analysis
  • Familiarity with the concepts of limit inferior (lim inf) and limit superior (lim sup)
  • Knowledge of bounded sequences in R
  • Basic skills in manipulating inequalities and limits
NEXT STEPS
  • Study the properties of limit inferior and limit superior in detail
  • Explore bounded sequences and their implications in real analysis
  • Learn about theorems related to the addition of sequences and their limits
  • Practice problems involving sequences and limits to reinforce understanding
USEFUL FOR

Students preparing for analysis exams, particularly those struggling with sequences and limits, as well as educators seeking to clarify these concepts for their students.

retspool
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I have analysis quiz tomorrow and i am really poor at sequences.

I don't know where to begin

Let (sn) and (tn) be sequences in R. Assume that (sn) is bounded.

Prove that liminf(sn +tn)≥liminfsn +liminftn,

where we define −∞ + s = −∞ and +∞ + s = +∞ for any s ∈ R.

-thanks
 
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Ok, what did you try already?
 
I got it,

I had to solve a problem before this one which gave me the result
lim infSn = -lim sup(-Sn)

And from a solved example i got

lim Sup(sn + tn) < lim supSn + lim SupTn

so multiplying b.s by (-1) and using -Sn instead for
we get

-lim Sup(-Sn - T) > lim Sup(-Sn) + lim Sup(-Tn)

There fore

lim Inf(Sn + Tn) > lim InfSn + lim InfTn

I had overlooked the solved example.
 

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