Analytic Function II: Complex Calculation

  • Context: MHB 
  • Thread starter Thread starter asqw121
  • Start date Start date
  • Tags Tags
    Function
Click For Summary
SUMMARY

The discussion centers on the analytic function defined by the equation p(z)=A(z-z1)...(z-zn), where A and z1...zn are complex numbers and A is non-zero. Participants are encouraged to demonstrate the relationship P'(z)/P(z)=∑ (1/(z-zj)) for z not equal to z1...zn. The conversation emphasizes the importance of showing attempted solutions to facilitate effective assistance from others.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with analytic functions and their definitions
  • Knowledge of differentiation in the context of complex analysis
  • Experience with summation notation and its application in mathematical proofs
NEXT STEPS
  • Study the properties of analytic functions in complex analysis
  • Learn about the application of the Cauchy-Riemann equations
  • Explore the concept of residues and their role in complex integration
  • Investigate the implications of the logarithmic derivative in complex functions
USEFUL FOR

Mathematicians, students of complex analysis, and anyone seeking to deepen their understanding of analytic functions and their applications in mathematical proofs.

asqw121
Messages
5
Reaction score
0
Let p(z)=A(z-z1)...(z-zn) where A and z1...zn are complex numbers and A not equal to 0 . Show that
P'(z)/P(z)=∑ (1/(z-zj)) z not equal z z1...zn
 
Physics news on Phys.org
Re: Analytic function

What have you tried? This isn't the place to dump homework and collect answers :(
 
Re: Analytic function III

Already try hard but I really stuck on this question
Please help
 
Re: Analytic function III

asqw121 said:
Already try hard but I really stuck on this question
Please help

If you show what you have tried, then our helpers can help, otherwise they are left to do the problem for you, which is of little help to you as far as you being able to work this problem and others like it yourself.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K