Analytic mapping of unit disc onto itself with two fixed pts.

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SUMMARY

The discussion centers on proving that a 1-1 analytic mapping of the unit disc onto itself, with two fixed points within the disc, must be the identity function f(z) = z. The participants reference the Schwarz lemma as a crucial theorem that supports this conclusion. The fixed points, denoted as a and b, satisfy f(a) = a and f(b) = b, leading to the determination that no other function can fulfill these criteria within the given constraints.

PREREQUISITES
  • Understanding of complex analysis, specifically analytic functions
  • Familiarity with the properties of the unit disc in the complex plane
  • Knowledge of the Schwarz lemma and its implications
  • Concept of fixed points in the context of complex mappings
NEXT STEPS
  • Study the Schwarz lemma in detail to understand its applications in complex analysis
  • Explore the properties of 1-1 analytic functions and their mappings
  • Investigate fixed point theorems in complex analysis
  • Review examples of analytic functions that map the unit disc onto itself
USEFUL FOR

Students and professionals in mathematics, particularly those studying complex analysis, as well as anyone interested in the properties of analytic functions and fixed point theory.

d2j2003
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Homework Statement



let f(z) be a 1-1 analytic mapping of unit disc |z|<1 onto itself with two fixed points in |z|<1 Show that f(z)=z


Homework Equations



none

The Attempt at a Solution



I'm thinking there has to be a theorem or something that I am missing for this.. But I'm not really sure where to get started..

To start, let a and b be the two fixed points in |z|<1, then f(a)=a and f(b)=b and I am sure there is a way to show that the only function that does this is f(z)=z not sure how though...
 
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Try thinking about the Schwarz lemma.
 
Got it, Thanks!
 

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