Analyzing One-Sided Limits in e^(1/(6-x)) as x Approaches 6+

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Homework Help Overview

The discussion revolves around evaluating the one-sided limit of the function e^(1/(6-x)) as x approaches 6 from the right. Participants are analyzing the behavior of the function near this point and comparing their findings with a provided answer in a textbook.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster expresses confusion regarding the limit's value, noting a discrepancy between their graphical observation and the textbook answer. Participants explore the limit of 1/(6-x) as x approaches 6 from the right, leading to discussions about its implications for the limit of the exponential function.

Discussion Status

Participants are actively engaging with the problem, questioning the validity of the textbook answer and clarifying the behavior of the limit. There is a recognition of differing interpretations of the limit's value, with some suggesting that the textbook may be incorrect.

Contextual Notes

There is an underlying assumption that the limit should yield a specific value, which is being challenged based on the participants' analysis. The discussion highlights the importance of understanding the behavior of functions as they approach critical points.

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lim e^(1/(6-x))
x->6+

Was wondering how to solve for this limit analytically. I plotted it and see it going to 0, but that is not the answer in the book.
 
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tsaitea said:
lim e^(1/(6-x))
x->6+

Was wondering how to solve for this limit analytically. I plotted it and see it going to 0, but that is not the answer in the book.
Hello tsaitea. Welcome to PF !

What is [itex]\displaystyle \lim_{x\to6^{+}}\,\frac{1}{6-x}\ ?[/itex]
 
oh -infinity, but the answer is e^(17/3)?, maybe the book is wrong then?
 
tsaitea said:
oh -infinity, but the answer is e^(17/3)?, maybe the book is wrong then?
Actually [itex]\displaystyle \ \ \lim_{x\to6^{+}}\,\frac{1}{6-x}=-\infty\ .[/itex]

If the problem you were given was to find [itex]\displaystyle \ \ \lim_{x\to6^{+}}\,e^{1/(6-x)}\,,\[/itex] then the book is wrong if it gives the answer as e^(17/3) . You were right in your original post to say the answer is zero.
 
Okay, thanks so much!
 

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