(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 9.00-kg hanging object is connected, by a light, inextensible cord over a light, frictionless pulley, to a 5.00-kg block that is sliding on a flat table. Taking the coefficient of kinetic friction as .200, find the tension in the string

2. Relevant equations

F = ma

3. The attempt at a solution

Fk = ma

a = (9.8 N friction force)/(5.00 kg) = 1.96 which is approximately 2

ΣFx= T - Fk = ma

T = Fk + ma

T = (9.8N) + total mass 14N(1.96 m/s^2)

T = 37.24 or if you use 2 for the acceleration you get 37.8 which is the right answer

Did I do this right?

Please help me to understand why.

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# Analyzing Tension Forces with friction

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