Angle Between Hour & Second Hand:130.25° or 133°?

  • Thread starter Thread starter ador250
  • Start date Start date
  • Tags Tags
    Clock
Click For Summary

Homework Help Overview

The discussion revolves around calculating the angle between the hour and second hands of a clock at a specific time, 10:20:30 AM. The original poster expresses confusion regarding two different angle measurements: 130.25° and 133°.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the reasoning behind the calculations for the hour and second hands' positions. They discuss the method of determining the angle based on the time elapsed and question the validity of the alternative angle calculation.

Discussion Status

The discussion includes attempts to clarify the reasoning behind both angle measurements. Some participants provide insights into potential errors in the calculations, particularly regarding the treatment of seconds and the contributions of the minute hand. There is no explicit consensus on which angle is correct, but the exploration of reasoning is ongoing.

Contextual Notes

Participants note the possibility of errors in the original poster's calculations, particularly in how the seconds were factored into the overall angle determination. The discussion reflects on the assumptions made in the calculations without resolving them.

ador250
Messages
2
Reaction score
0
a clock was set 10 am 20 minutes 30 second ? what will be the angle between hour & second hand ??

ans : 130.25° or 133° which one is correct? I'm confused
 
Physics news on Phys.org
The line of reasoning should be as follows:-

It takes 12 hours for the hour hand to make a complete 360° rotation, i.e.

12 hours-------> 360°
==> 1 hour -------> 30°
==> 60 min -------> 30°
==> 1 min -------> 0.5°
==> 20.5 min -------> 10.25°

So, in a time period of 20.5 minutes, the hour hand would have traversed 10.25°.

Now, when the clock shows 10 A.M exactly, the hour hand has traversed 300° (since for each hour, the hour hand traverses 30°. So, after 10 hours exactly, it has traversed 300°). And in a further 20 minutes and 30 seconds, i.e. 20.5 minutes, it would have traversed 10.25° further, as we have just calculated above. So, the total angular distance traversed by the hour hand is (300+10.25)° = 310.25°.

Now, the second hand is at the exact position '6' in the clock (since it travels for a period of 30 seconds), and hence has traversed exactly half of the clock, thus traveling an angular distance of 180°.

Therefore, the angle between the hour hand and the second hand would be (310.25 - 180)° = 130.25°.

Hope that makes it clear! :smile:
 
The more interesting question is how the other answer was obtained.

Offhand, it looks like a factor of 12 got erroneously applied to the seconds correction.
 
jbriggs444 said:
The more interesting question is how the other answer was obtained.

Offhand, it looks like a factor of 12 got erroneously applied to the seconds correction.

The best explanation I could come up with is, that the OP first figured that at exactly 10:20 A.M, the hour hand would have traversed 310°. Then, for the remaining 30 seconds, he mistakenly calculated the angular distance traversed by the minute hand, which turns out to be 3°, and then added it to the angular distance traversed by the hour hand, giving him the final value of the latter as 313°. And since the second hand has traversed 180°, he obtains (313 - 180)° = 133°, which is false.
 
Ryuzaki said:
... Then, for the remaining 30 seconds, he mistakenly calculated the angular distance traversed by the minute hand, which turns out to be 3°...

Nice. That fits.
 
got it man...thanks :)
 

Similar threads

Replies
24
Views
4K
Replies
7
Views
3K
Replies
30
Views
7K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 10 ·
Replies
10
Views
2K