# Atomic clock: energy between two levels

## Homework Statement

With the atomic clock a second is defined as the time it takes for EM radiation to oscillate 9192631770 times, which equals the energy gap between two energy levels of a caesium-133 atom. Note: it's a translation and the term used with the oscillation is "oscillation periods"

## Homework Equations

Calculate the energy difference (in eV)

## The Attempt at a Solution

[/B]
At first I took the expression "oscillation periods" to mean that I had to use the T=1/f relation and insert it in the E=hf equation. However since T is in seconds and f means turns or oscillations, I went with f=9192631770.

So, I have:
E = hf
= 6.626*10^(-34) Js * 9192631770 /s
= 6.091*10^(-24) J
= 3.8 * 10^(-5) eV

I just hope to check whether I made the right assumptions and conversions, thank you.

haruspex
Homework Helper
Gold Member

## Homework Statement

With the atomic clock a second is defined as the time it takes for EM radiation to oscillate 9192631770 times, which equals the energy gap between two energy levels of a caesium-133 atom. Note: it's a translation and the term used with the oscillation is "oscillation periods"

## Homework Equations

Calculate the energy difference (in eV)

## The Attempt at a Solution

[/B]
At first I took the expression "oscillation periods" to mean that I had to use the T=1/f relation and insert it in the E=hf equation. However since T is in seconds and f means turns or oscillations, I went with f=9192631770.

So, I have:
E = hf
= 6.626*10^(-34) Js * 9192631770 /s
= 6.091*10^(-24) J
= 3.8 * 10^(-5) eV

I just hope to check whether I made the right assumptions and conversions, thank you.
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