- #1

- 11

- 4

Say there are two vectors in the XY-plane that we want to find the angle between:

**A**= -2.00

**i**+ 6.00

**j**

B= 2.00

B

**i**- 3.00

**j**

The method to do this would be to work out the

*scalar*product of the vectors, calculate the magnitude of each vector, and use these to determine the angle via this relationship:

**A**⋅

**B**= AB cos ∅

In the example above, this gives a correct angle of 165°.

However, I feel like it should be possible to arrive at the same answer using a

*vector*product method instead. So I tried calculating the vector product, and used it with the calculated magnitudes of the vectors and the following relationship:

**A**X

**B**= AB sin Φ

However, using this method results in an angle of 15.3°.

I must be missing something in the way all of this works and wondered if anyone could provide me with the knowledge I'm missing!

Thanks!

Andy