Angle bisectors of a quadrilateral

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SUMMARY

The discussion centers on the conditions under which the angle bisectors of a quadrilateral intersect at a single point. It is established that a quadrilateral can be inscribed in a circle if and only if its opposite angles are supplementary. The key theorem referenced is the Pitot Theorem, which provides the necessary conditions for a quadrilateral to have an incircle that is tangent to all its sides. This theorem is crucial for understanding the relationship between angle bisectors and the existence of an incircle.

PREREQUISITES
  • Understanding of quadrilaterals and their properties
  • Familiarity with angle bisectors in geometry
  • Knowledge of the Pitot Theorem
  • Basic concepts of inscribed and circumscribed circles
NEXT STEPS
  • Study the Pitot Theorem in detail
  • Explore the properties of cyclic quadrilaterals
  • Learn about the construction of incircles in polygons
  • Investigate the relationship between angle bisectors and perpendiculars in geometry
USEFUL FOR

Students of geometry, mathematics educators, and anyone interested in advanced geometric properties and theorems related to quadrilaterals.

dalcde
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What are the conditions to have such that the angle bisectors of a quadrilateral meet at a single point?

Btw, should I put this in the (Topology and) Geometry forums, or is it for more advanced geometry?
 
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hi dalcde! :smile:

hmm … angle bisectors :rolleyes:

hint: perpendiculars? :wink:
 
The perpendiculars are equal?

Actually that's what I was starting with. You can put a circle around a quadrilateral (enclosing the quadrilateral inside) if and only if opposite angles of the quadrilateral are supplementary. I wanted to know under what conditions will it be possible to put a circle inside that is tangent to all of the side. (analogous to the incenter of a triangle) If having equal perpendiculars is what you meant, I would be going in circles, unless you have some ways to determine if you can put a circle inside, which would be really appreciated.
 
Anyway, I've found the answer - Pitot Theorem. Thanks anyway.
 

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