Angle due to angular acceleration

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SUMMARY

The discussion focuses on calculating the banking angle of a curve with a radius of 54.7 m for a car with a mass of 2.4 Mg traveling at a speed of 51 km/hr. The relevant equations include centripetal acceleration (a = v²/r) and the tangent of the banking angle (tan(theta) = opposite/adjacent). The acceleration due to gravity is specified as 9.8 m/s². The participants emphasize the importance of properly resolving forces at an angle to derive the correct banking angle.

PREREQUISITES
  • Understanding of centripetal acceleration (a = v²/r)
  • Knowledge of trigonometric functions, specifically tangent (tan(theta))
  • Familiarity with Newton's second law of motion (f = ma)
  • Basic principles of forces acting on an object in circular motion
NEXT STEPS
  • Calculate the banking angle using the formula tan(theta) = v²/(rg)
  • Explore the effects of friction on banking angles in different scenarios
  • Study the dynamics of vehicles on banked curves in physics textbooks
  • Investigate real-world applications of banking angles in road design and safety
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for examples of practical applications of trigonometry and dynamics in vehicle motion.

notsam
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Homework Statement

A curve of radius 54.7 m is banked so that
a car of mass 2.4 Mg traveling with uniform
speed 51 km/hr can round the curve without
relying on friction to keep it from slipping on
the surface.At what angle is the curve banked? The
acceleration due to gravity is 9.8 m/s2 .
Answer in units of degrees.



Homework Equations

a=v^2/r, tan(theta)=o/a, f=ma, f=mv^2/r



The Attempt at a Solution

Ok so here's what I think. The basic equation should look something like this. ma=mv^2/r except its at an angle so. Maybe tan(theta)ma=mv^2/r?
 
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hi notsam! :smile:

(try using the X2 icon just above the Reply box :wink:)
notsam said:
Ok so here's what I think. The basic equation should look something like this. ma=mv^2/r except its at an angle so. Maybe tan(theta)ma=mv^2/r?

come off it! :rolleyes:

to pass the exams, you need to give a proper explanation …

now which direction do you think you should be taking components in (and why)? :smile:
 

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