A cannon is aimed at a target located 72m away from the cannon and 20m above the ground. The cannon ball, when fired, will have the initial speed of 32m/s, but it has to clear a 13m wall between the cannon and the target as, shown. At what angle should the cannon be fired?
The Attempt at a Solution
I have tried to do this question many different ways, but I have not been able to find the correct answer.
Here is what I have tried:
For the first wall Dx= 15, Dy=13, Vx=32cos([tex]\theta[/tex]) Voy=32sin([tex]\theta[/tex])
and since Vx=Dx/t ,Dx/Vx=t then t=15/32cos([tex]\theta[/tex])
I am going to stop here for help because I don't think I am doing this correctly.
Thank you! =)