Angle that the stone is thrown off of the cliff?

  • Thread starter balling12
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  • #26
Cyosis
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So what is the initial downward speed of the stone?
 
  • #27
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The equation applies to each direction. You can't mix them up. What we're interested in is the vertical direction, the direction in which the ball falls due to gravity. The initial speed in the vertical direction is what? (16 m/s is the speed in the horizontal direction)
If the initial speed in the vertical direction is not g then i dont know.
 
  • #28
Cyosis
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G is an acceleration, acceleration is not speed. The stone starts from a certain initial vertical speed and is then sped up by gravity. What is the value of this initial speed?
 
  • #29
dx
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g is the acceleration, not the speed. The initial speed in the vertical direction is zero, because the velocity only has a horizontal component of magnitude 16 m/s.
 
  • #30
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so my equation should be: 62= (0)t+ 1/2(-9.8)t^2
 
  • #31
Cyosis
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Almost. You have a sign wrong, you can see this because you will need to take the root of a negative number in the form you have written down.
 
  • #32
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t= 3.54 sound about right?
 
  • #33
Cyosis
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I get t=3.555=3.6. So you have made a minor rounding error other than that it is correct.
 

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