Angle that the stone is thrown off of the cliff?

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SUMMARY

The discussion centers on a physics problem involving a stone thrown horizontally from a cliff at a speed of 16.0 m/s, with the cliff height being 62.0 m. The correct approach to determine the time of impact and the angle of impact is clarified through the use of kinematic equations. The time of fall is calculated using the equation s = ut + ½at², where the initial vertical speed (u) is 0 m/s and acceleration (a) is -9.8 m/s². The final calculation yields a time of approximately 3.56 seconds for the stone to strike the beach below.

PREREQUISITES
  • Understanding of kinematic equations, specifically s = ut + ½at²
  • Knowledge of horizontal and vertical motion components
  • Familiarity with gravitational acceleration (9.8 m/s²)
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation and application of kinematic equations in projectile motion
  • Learn about the components of motion in two dimensions
  • Explore the concept of free fall and its relation to gravitational acceleration
  • Practice solving similar physics problems involving horizontal projectile motion
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding projectile motion and its calculations.

  • #31


Almost. You have a sign wrong, you can see this because you will need to take the root of a negative number in the form you have written down.
 
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  • #32


t= 3.54 sound about right?
 
  • #33


I get t=3.555=3.6. So you have made a minor rounding error other than that it is correct.
 

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