1. The problem statement, all variables and given/known data To lower himself from a balcony an 80kg stuntman grabs a rope connected to a 400kg cylinder with a 1.2m diameter that is free to rotate about its axis of symmetry. What is the stuntman's acceleration as he falls? 2. Relevant equations I missed this on a homework assignment. I know the correct answer is 2.86m/s2 but I can't find what I did wrong. 3. The attempt at a solution moment of inertia for a cylinder: I=1/2 Mr2 radius of cylinder = 0.6m torque applied by stuntman = mgr = 80kg * 9.8m/s2 * 0.6m = 470.4Nm Using t = Iα 470.4Nm = (0.5 * 400kg * 0.6m2)α α = 470.4Nm / (0.5 * 400kg * 0.6m2) = 6.53rad/s2 a = αr = 6.53rad/s2 * 0.6m = 3.92m/s2 What am I missing?