A bicycle has wheels of 0.8 m diameter. The bicyclist accelerates from rest with constant acceleration to 22 km/h in 13.7 s. What is the angular acceleration of the wheels? relevant equations: omega = omega initial + alpha * t 22km/h = 6.11m/s I did 6.11m/s * 13.7s = 83.7207 to get the velocity then I divided it by .4m to get 209.30175 Im not sure what I should do next I have another question which is related to the same topic: A block of 2kg falls with a speed of 3.9m/s from rest to a distance of 2.5m, its acc. is 3.0m/s from a pulley of radius of 8cm. (b) What is the angular velocity of the pulley at this time? I used V = R/omega = 3.9m/s = .08m / omega omega = .02 This is wrong is my approach wrong?