- #1
daltomagne
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The blades in a blender rotate at a rate of 6100rpm. When the motor is turned off during operation, the blades slow to rest in 4.7s
What is the angular acceleration as the blades slow down?
f=6100rpm=366000rps
dt=4.7s
w=2(pi)f
angular acceleration=dw/dt
w=2(pi)3.66*10^5=2.3*10^6 rad/s
wI=2.3*10^6 rad/s
wf=0
angular a=(0-(2.6*10^6))/4.7s=-489286 rad/s2
I thought I was doing it right, but it appears not.
What is the angular acceleration as the blades slow down?
f=6100rpm=366000rps
dt=4.7s
w=2(pi)f
angular acceleration=dw/dt
w=2(pi)3.66*10^5=2.3*10^6 rad/s
wI=2.3*10^6 rad/s
wf=0
angular a=(0-(2.6*10^6))/4.7s=-489286 rad/s2
I thought I was doing it right, but it appears not.