clope023
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[SOLVED] angular acceleration of a Propeller
An airplane propeller is rotating at 2000rev/min .
[tex]\omega[/tex]z = 209rad/s
How long in seconds does it take for the propeller to turn through 40degrees?
[tex]\theta[/tex] = 1/2[tex]\omega[/tex]t
[tex]\omega[/tex]z = d[tex]\theta[/tex]/dt
40degrees = (2[tex]\Pi[/tex]/360degrees) = .698rad
209rad/s = .698rad/t
209rad/s(t) = .698rad
t = .698rad/209rad/s
t = .0033s wrong
I'm sure I'm using the right equations, does anyone know what I'm doing wrong?
any help is appreicated, I think I'm missing something obvious just not sure what it is.
Homework Statement
An airplane propeller is rotating at 2000rev/min .
[tex]\omega[/tex]z = 209rad/s
How long in seconds does it take for the propeller to turn through 40degrees?
Homework Equations
[tex]\theta[/tex] = 1/2[tex]\omega[/tex]t
[tex]\omega[/tex]z = d[tex]\theta[/tex]/dt
The Attempt at a Solution
40degrees = (2[tex]\Pi[/tex]/360degrees) = .698rad
209rad/s = .698rad/t
209rad/s(t) = .698rad
t = .698rad/209rad/s
t = .0033s wrong
I'm sure I'm using the right equations, does anyone know what I'm doing wrong?
any help is appreicated, I think I'm missing something obvious just not sure what it is.