(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] angular acceleration of a Propeller

1. The problem statement, all variables and given/known data

An airplane propeller is rotating at 2000rev/min .

[tex]\omega[/tex]z = 209rad/s

How long in seconds does it take for the propeller to turn through 40degrees?

2. Relevant equations

[tex]\theta[/tex] = 1/2[tex]\omega[/tex]t

[tex]\omega[/tex]z = d[tex]\theta[/tex]/dt

3. The attempt at a solution

40degrees = (2[tex]\Pi[/tex]/360degrees) = .698rad

209rad/s = .698rad/t

209rad/s(t) = .698rad

t = .698rad/209rad/s

t = .0033s wrong

I'm sure I'm using the right equations, does anyone know what I'm doing wrong?

any help is appreicated, I think I'm missing something obvious just not sure what it is.

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# Angular acceleration of a Propeller

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