[SOLVED] angular acceleration of a Propeller 1. The problem statement, all variables and given/known data An airplane propeller is rotating at 2000rev/min . [tex]\omega[/tex]z = 209rad/s How long in seconds does it take for the propeller to turn through 40degrees? 2. Relevant equations [tex]\theta[/tex] = 1/2[tex]\omega[/tex]t [tex]\omega[/tex]z = d[tex]\theta[/tex]/dt 3. The attempt at a solution 40degrees = (2[tex]\Pi[/tex]/360degrees) = .698rad 209rad/s = .698rad/t 209rad/s(t) = .698rad t = .698rad/209rad/s t = .0033s wrong I'm sure I'm using the right equations, does anyone know what I'm doing wrong? any help is appreicated, I think I'm missing something obvious just not sure what it is.