Angular Acceleration of a Pulley Supporting Two Hanging Masses

Click For Summary
SUMMARY

The discussion focuses on calculating the angular acceleration of a grooved drum supporting two hanging masses, given a frictional moment of 2 N m. The user initially calculated the angular acceleration as α = 2.33 rad/s², but this result was incorrect due to the omission of the angular acceleration of the two masses (12 kg and 7 kg). The correct approach requires incorporating the effects of these masses' accelerations, leading to the expected answer of α = 0.622 rad/s².

PREREQUISITES
  • Understanding of dynamics and rotational motion principles
  • Familiarity with moment of inertia calculations
  • Knowledge of Newton's second law for rotation
  • Ability to apply torque and angular acceleration equations
NEXT STEPS
  • Review the concept of angular acceleration in systems with multiple masses
  • Learn about the relationship between linear and angular motion
  • Study the effects of friction on rotational dynamics
  • Explore advanced problems involving pulleys and multiple hanging masses
USEFUL FOR

Students studying dynamics, mechanical engineers, and anyone involved in solving problems related to rotational motion and pulleys.

wingman358
Messages
18
Reaction score
1

Homework Statement



Hi all! I'm working on a dynamics homework and have hit a wall here:

d27a9810-5a81-45a4-b062-9839faa86a69-original.png


"If the frictional moment at the pivot O is 2 N m, determine the angular acceleration of the grooved drum, which has a mass of 8 kg and a radius of gyration k = 225 mm.

Ans: α = 0.622 rad/s^2 "

Homework Equations



M = m g r

ƩM = I α

I = m k^2

The Attempt at a Solution



The two masses exert moments about O, so my first step is to sum the moments about the pivot O:

ƩM = (12 kg)(9.81 m/s^2)(0.2 m) - (7 kg)(9.81 m/s^2)(0.3 m)
ƩM = 2.943 N m

These moments are resisted by the frictional moment such that:

ƩM = (2.943 N m) - (2 N m)
ƩM = 0.943 N m

Next we need the moment of inertia of the pulley:

I = m_pulley * k^2
I = (8 kg)(0.225 m)^2
I = 0.405 kg m^2

Finally we can solve for angular acceleration:

ƩM = I α
so
α = ƩM / I
α = (0.943 N m) / (0.405 kg m^2)
α = 2.33 1 / s^2

My analysis seems reasonable and I come up with the right units, but it is not very close to the given answer.

Am I doing something wrong?
 
Last edited:
Physics news on Phys.org
We cannot assume that there is no acceleration on the two objects(12kg and 7kg)
 
Last edited by a moderator:
wingman358 said:

Homework Statement



Hi all! I'm working on a dynamics homework and have hit a wall here:

View attachment 152095

"If the frictional moment at the pivot O is 2 N m, determine the angular acceleration of the grooved drum, which has a mass of 8 kg and a radius of gyration k = 225 mm.

Ans: α = 0.622 rad/s^2 "

Homework Equations



M = m g r

ƩM = I α

I = m k^2

The Attempt at a Solution



The two masses exert moments about O, so my first step is to sum the moments about the pivot O:

ƩM = (12 kg)(9.81 m/s^2)(0.2 m) - (7 kg)(9.81 m/s^2)(0.3 m)
ƩM = 2.943 N m

These moments are resisted by the frictional moment such that:

ƩM = (2.943 N m) - (2 N m)
ƩM = 0.943 N m

Next we need the moment of inertia of the pulley:

I = m_pulley * k^2
I = (8 kg)(0.225 m)^2
I = 0.405 kg m^2

Finally we can solve for angular acceleration:

ƩM = I α
so
α = ƩM / I
α = (0.943 N m) / (0.405 kg m^2)
α = 2.33 1 / s^2

My analysis seems reasonable and I come up with the right units, but it is not very close to the given answer.

Am I doing something wrong?

You forgot to consider the acceleration of the angles for the two masses . That is why you acceleration is too fast. the angular acceleration of the 12kg mass and 7kg mass are missing
 
Last edited by a moderator:
Bemberson said:
You forgot to consider the acceleration of the angles for the two masses . That is why you acceleration is too fast. the angular acceleration of the 12kg mass and 7kg mass are missing
This thread is 10 years old. The user who posted it is unlikely to profit from your remark, but thank you for posting.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
848
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 4 ·
Replies
4
Views
13K
Replies
8
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K