Angular Acceleration of a Pulley

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To find the angular acceleration of a pulley with a radius of 0.1 m and a moment of inertia of 0.15 kg*m² under a force of 12 N, Newton's second law for rotation is applied. The formula used is angular acceleration = torque / moment of inertia, where torque is calculated as force multiplied by radius. Substituting the values gives angular acceleration = (12 N * 0.1 m) / 0.15 kg*m², resulting in an angular acceleration of 8.0 rad/s². This calculation confirms the correct application of the principles of rotational dynamics. The solution effectively demonstrates the relationship between force, torque, and angular motion.
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Homework Statement


A cable is around a pulley with:
radius = 0.1 m
moment of inertia = 0.15 kg * m(squared)

The cable receives a pull of:
force = 12 N

Find the magnitude of the resulting angular acceleration of the puller.

Homework Equations



Average angular acceleration = Change in angular velocity / Elapsed time
Average angular velocity = Angular displacement / Elapsed time

The Attempt at a Solution



I'm completely stuck since none of the given information can be used in the equations listed above.
 
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Hint: Consider Newton's 2nd law for rotation.
 
Thanks, I think I have it. So:
angular acceleration = 12 * 0.10 / 0.15 = 8.0 rad/s(squared)
?
 
You got it.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

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