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Angular Acceleration of a Pulley

  1. Jul 28, 2009 #1
    1. The problem statement, all variables and given/known data
    A cable is around a pulley with:
    radius = 0.1 m
    moment of inertia = 0.15 kg * m(squared)

    The cable receives a pull of:
    force = 12 N

    Find the magnitude of the resulting angular acceleration of the puller.

    2. Relevant equations

    Average angular acceleration = Change in angular velocity / Elapsed time
    Average angular velocity = Angular displacement / Elapsed time

    3. The attempt at a solution

    I'm completely stuck since none of the given information can be used in the equations listed above.
     
  2. jcsd
  3. Jul 28, 2009 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Hint: Consider Newton's 2nd law for rotation.
     
  4. Jul 28, 2009 #3
    Thanks, I think I have it. So:
    angular acceleration = 12 * 0.10 / 0.15 = 8.0 rad/s(squared)
    ???
     
  5. Jul 29, 2009 #4

    Doc Al

    User Avatar

    Staff: Mentor

    You got it.
     
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