Angular and Linear Acceleration on a Wheel

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SUMMARY

The discussion focuses on the calculation of angular and linear acceleration for a wheel with a diameter of 68 cm, which accelerates uniformly from 150 rpm to 270 rpm in 4.1 seconds. The angular acceleration is determined to be 3.1 rad/s². After 1.6 seconds of acceleration, the final angular velocity is calculated as 20.61174 rad/s, leading to a final linear velocity of 7.0079916 m/s. The radial component of linear acceleration, specifically the centripetal acceleration, is clarified as ω²r, addressing initial confusion regarding the terminology used.

PREREQUISITES
  • Understanding of angular acceleration and its calculation
  • Familiarity with linear velocity and its relationship to angular velocity
  • Knowledge of centripetal acceleration and its formula
  • Basic proficiency in physics equations related to rotational motion
NEXT STEPS
  • Study the derivation and application of the centripetal acceleration formula (a_c = ω²r)
  • Explore the relationship between angular velocity and linear velocity in rotational dynamics
  • Learn about uniform angular acceleration and its implications in real-world scenarios
  • Investigate the effects of varying wheel diameters on acceleration calculations
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PeachBanana
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Homework Statement


A 68 cm diameter wheel accelerates uniformly about its center from 150 rpm to 270 rpm in 4.1 s.

1. Determine its angular acceleration. α = 3.1 rad./s^2

2. Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.6 s after it has started accelerating.


Homework Equations



ω final = ω initial + αt
v final = v initial + at
ω * r = v

The Attempt at a Solution



1. (15.7079 rad./s) + (3.0649 rad./s^2)(1.6s)
ω = 20.61174 rad./s

(20.61174 rad./s)(0.34m) = 7.0079916 m/s (final velocity)
(15.7079 rad./s)(0.34m) = 5.340686 m/s (initial velocity)

7.0079916 m/s - 5.340686 m/s / 1.6 s = 1.042066 m/s^2
 
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Hi PeachBanana! :smile:
PeachBanana said:
2. Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.6 s after it has started accelerating.

No, I think they're asking for the centripetal acceleration (ω2r).
 
tiny-tim: Thank you so much. That is much clearer now. The way it was worded was strange.
 

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