# Getting frequency from angular momentum?

• deathkamp
In summary, the conversation discusses a problem involving a right circular cylinder with a diameter of .115 meters and a mass of .03 kg rotating at 300 rev per min. An ant with a mass of .01 kg collides with the cylinder and lands on the rim, treated as a point mass. The objective is to find the final frequency in rev/min for the cylinder/ant system. The approach involves using principles of rotational quantities, specifically angular momentum, and conservation of angular momentum. The final answer for the final frequency is 179.8 rev/min.
deathkamp

## Homework Statement

[/B]
I messed up the original thread in terms of information, so I made a new better one. Ok here goes:

I have a problem where a right circular cylinder with diameter .115meter and a mass of .03kg is rotating at 300 rev per min. Now an Ant which weighs .01kg collides with the rotating cylinder and lands on the rim of the cylinder. The Ant is treated as a point mass.

So I am looking for the final frequency in rev/min of the cylinder/Ant system? Which is part a of the problem?

This is the farthest I got, and I wanted to know if my work is good so far and how to use the angular momentum to get the final frequency?

## Homework Equations

I(inertia)=mr^2 this is for point mass
angular momentum is L=I*w

## The Attempt at a Solution

I=(.01kg)*(.0575m^2), so I=33.06*10^-6 inertia for the point mass after it landed on the cylinder

#### Attachments

• Screen Shot 2016-06-21 at 8.35.02 PM.png
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How many revs/sec is it? How many radians in one revolution?

Read Simon's post on that other thread again. Don't start with equations, think about principles. See if you can reply to this without mentioning a single equation :-) If you get that right, then you can think about which equations might be relevant.

So which principle should you apply here?

@haruspex 300 rev/min =31.42 rad/sec(300/60=5 5*2pi= 31.42rad/sec), also since you stated it has nothing to do with the radius this means w=31.42 rad/sec, which saves me some work. The thing I don't get is how do I get the wfinal which is after the ant landed so that I can then convert into the final frequency's rev/min ? I mean even if I get L(angular momentum) how would that help me get Ffinal or wfinal, especially since the w I am using is using the initial frequency of 300 rev/min?

@ CWatters the principle I am using is related to rotational quantities or to be more specific the angular momentum. Since the kinetic energy changes its not conservation of kinetic energy. But I don't see the relationship with getting the angular momentum and wfinal or the final frequency?

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deathkamp said:
@ CWatters the principle I am using is related to rotational quantities or to be more specific the angular momentum. Since the kinetic energy changes its not conservation of kinetic energy. But I don't see the relationship with getting the angular momentum and wfinal or the final frequency?
The problem is a rotational version of a linear collision problem. The same concepts apply as for linear collisions, only using rotational quantities rather than linear ones (even the equations are the same).

What type of collision is portrayed? What is conserved in that type of collision?

I was doing some thinking an made the conclusion that the conservation of angular momentum is conserved therefore I1*w1=I2*w2. Where I is the inertia So w2=(r1/r2)^2*w1 Where w2 is the final angular velocity an I can get the final frequency from that. My problem is since the radius does not change its basically w1 *1 which gives the final angular velocity = to the initial. Is this a correct assumption?

deathkamp said:
I was doing some thinking an made the conclusion that the conservation of angular momentum is conserved therefore I1*w1=I2*w2.
I1 is for just the cylinder, but I2 includes the ant.

So for getting I2 the mass will be the cylinder mass + the ants mass correct? And my intial assumption about w2=w1 cause the radiuses does not change is that correct? Since w2=(r1/r2)^2*w1?

deathkamp said:
So for getting I2 the mass will be the cylinder mass + the ants mass correct
No, the moment of inertia, I2, will be the cylinder's moment of inertia about its axis plus the ant's moment of inertia about that axis.
deathkamp said:
And my intial assumption about w2=w1 cause the radiuses does not change is that correct
No, the angular velocity will change because the total moment of inertia changes while angular momentum stays constant.

CWatters
deathkamp said:
@ CWatters the principle I am using is related to rotational quantities or to be more specific the angular momentum. Since the kinetic energy changes its not conservation of kinetic energy. But I don't see the relationship with getting the angular momentum and wfinal or the final frequency?

Momentum/Angular Momentum is always conserved.

Alright beer with me on the math becasue I want to check my answers to both part a and b

Part A)
I1*w1=I2*w2

I1=.5*m*r2=.5*(.03*(.0575meter2)) = 49.5*10-6

The ants inertia is I=(.01*(.0575^2))= 33.06*10-6

I2=(49.5*10-6 + 33.06*10-6) = 82.56-6

w2=(49.5*10-6*31.42)/82.56*10-6

Am I good so far?

Part B)
Change in kinetic energy is the initial - final,

Kinitial=.5*I*w2=.5*(49.5*10-6)*(31.422)=24.43*10-3

Used I2 as I for k final
Kfinal=.5*I*w2=.5*(82.56*10-6)*(18.8^2)=14.59*10-3

The change in k is trivial so I won't compute it, but is everything good?

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deathkamp said:
The ants inertia is I=.5*(.01*(.0575^2))= 16.5*10-6
No. You got this right in your original post.

thank you, I fixed it now, the only thing that concerns me is for the Kfinal. I can just add both the ant and cylinder mass together, or must I find each of their kinetic energy separately then add them to get kfinal?

deathkamp said:
31.42/.0575meter
What formula leads to that calculation? And why do you want find the peripheral velocity? How do you normally calculate rotational KE?

Ah I used the wrong stuff, KE rotational is .5*I*w2, I corrected it. And for KE final i used I2 calculated value. Thanks guys.

## What is the relationship between angular momentum and frequency?

The frequency of an object's rotation is directly proportional to its angular momentum. This means that as the angular momentum increases, so does the frequency.

## How do you calculate the frequency from angular momentum?

The frequency can be calculated by dividing the angular momentum by 2π. This is known as the angular velocity.

## What is the significance of frequency in understanding an object's motion?

Frequency is an important factor in understanding the motion of an object because it tells us how many rotations or cycles an object undergoes in a given time period. This can help us determine the speed and direction of the object's motion.

## Can an object's angular momentum and frequency change?

Yes, an object's angular momentum and frequency can change. This can happen if there is a change in the object's mass, velocity, or radius of rotation.

## In what real-world applications is understanding frequency from angular momentum important?

Understanding frequency from angular momentum is important in a variety of fields, such as physics, engineering, and astronomy. It is used in the design and analysis of rotating machinery, as well as in the study of celestial bodies such as planets and stars.

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