Angular momentum of merry go round turntable

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SUMMARY

The discussion focuses on calculating the angular velocity of a merry-go-round turntable when a person runs along its edge. The scenario involves a 55 kg individual on a 6.5 m diameter turntable with a moment of inertia of 1700 kg m². By applying the conservation of angular momentum principle, the initial angular momentum (L_i) is zero, and the final angular momentum (L_f) can be expressed as the sum of the person's angular momentum and the turntable's angular momentum. The calculation leads to determining the angular velocity of the turntable in response to the person's movement.

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Hi, I got this question wrong on a test and am really quite lost about it. I'd appreciate somebody running me through it.

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"Suppose a 55 kg person stands at the edge of a 6.5 m diameter merry go round turntable that is mounted on a frictionless bearing and has a moment of inertia of 1700 kg m^2. The turntable is at rest initially, but when the person begins running at a speed of 3.8 m/s (with respect to the turntable) around its edge, the turntable begins to rotate in the opposite direction. Caculate the angular velocity of the table."

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So I set up conservation of angular momentum
L_f = L_i
and
(Iw)_f = (Iw)_i

Can somebody please help me from there?
 
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I guess you'd treat the person as a point mass, so the person has moment of inertia mr^2. Can you calculate his angular velocity?
 

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