Angular Momentum problem, Swinging door

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SUMMARY

The discussion focuses on calculating the final angular speed of a solid wood door after being struck by a mass of sticky mud. The door measures 1.00 m in width and 2.00 m in height, with a mass of 42.0 kg. The mud, weighing 0.400 kg, impacts the door at a velocity of 11.0 m/s. The conservation of angular momentum is applied, leading to the equation L_{mud}=L_{door&mud}, where the moment of inertia for the mud is treated as a point particle.

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sreya
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Homework Statement



A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 42.0kg . Initially open and at rest, the door is struck at its center by a handful of sticky mud with mass 0.400kg , traveling perpendicular to the door at 11.0m/s just before impact.

Find the final angular speed of the door.

Homework Equations



Conservation of angular momentum

[itex]rmvsin\theta=l[/itex]

The Attempt at a Solution



[itex]L_{mud}=L_{door\&mud}[/itex]

[itex]rmvsin\theta=(I_{door}+I_{mud})\omega[/itex]

[itex].5(.5)(14)sin(90^o)=(I_{door}+I_{mud})\omega[/itex]

How do I determine the inertias for the mud and the door??
 
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