Angular motion problem involving a car coming to a stop

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Homework Help Overview

The problem involves a car decelerating from an initial speed, with the goal of determining the number of revolutions its tires make before coming to a stop. The subject area includes concepts of angular motion and kinematics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculations related to the distance traveled during deceleration and the conversion of that distance into revolutions of the tires. There is a focus on verifying the mathematical steps and ensuring correct application of significant figures.

Discussion Status

The discussion is ongoing, with participants questioning the accuracy of the calculations and suggesting a review of the mathematical process. Some participants are exploring potential errors in the original poster's reasoning or calculations.

Contextual Notes

There is mention of significant figures and the need for accuracy in the calculations, indicating that precision may be a factor in the discussion. The original poster's calculations have not yielded the expected results, prompting further inquiry.

xregina12
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The driver of a car traveling at 12.0 m/s applies the brakes and undergoes a constnant decelertion of 1.90m/s^2.
How many revolutions does each tire make before the car comes to a stop assuming that the car does not skid and that the tires of radii of 0.40 m? answer in units of rev.

I used the equation Vf^2=Vi^2+2ad
0=144+2(-1.90)(d)
d=37.89meters
d=r(θ)
θ=37.89/0.40=94.725 radians
revolutions=94.725/(2pi)=115.076 revolutions.
However, I did not get a correct answer. Can anyone help?
 
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revolutions=94.725/(2pi)=115.076 revolutions.

Is this a typo? Check your math here.
 
I meant to write 15.075 and it's still not right though.
 
I don't see what's wrong with that answer. Are you using correct sig figs when you enter your answer?
 

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