The driver of a car traveling at 12.0 m/s applies the brakes and undergoes a constnant decelertion of 1.90m/s^2.(adsbygoogle = window.adsbygoogle || []).push({});

How many revolutions does each tire make before the car comes to a stop assuming that the car does not skid and that the tires of radii of 0.40 m? answer in units of rev.

I used the equation Vf^2=Vi^2+2ad

0=144+2(-1.90)(d)

d=37.89meters

d=r(θ)

θ=37.89/0.40=94.725 radians

revolutions=94.725/(2pi)=115.076 revolutions.

However, I did not get a correct answer. Can anyone help?

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# Homework Help: Angular motion problem involving a car coming to a stop

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