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Angular motion with constant acceleration

  1. Apr 19, 2008 #1
    [SOLVED] Angular motion with constant acceleration

    1. The problem statement, all variables and given/known data
    [​IMG]


    2. Relevant equations
    [tex]\varpi[/tex]= [tex]\varpi[/tex](inital) + [tex]\alpha[/tex]t


    3. The attempt at a solution

    I understood part A and Part b,
    What I don't understand is how to do Part C.
    What I did was divide the average angular velocity with acceleration. But I don't get why or a more understanding method to do this problem
     
  2. jcsd
  3. Apr 19, 2008 #2

    Hootenanny

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    The angular acceleration is a measure of the rate of change of angular velocity, in other words, provided that the angular acceleration is constant it is the change in angular velocity divided by the time taken. Mathematically, for constant acceleration ([itex]\alpha[/itex]),

    [tex]\alpha = \frac{\Delta \omega}{\Delta t}[/tex]

    Which can be rearranged,

    [tex]\Rightarrow \Delta t = \frac{\Delta \omega}{\alpha}[/tex]

    or,

    [tex]\Delta t = \frac{\omega_\text{final} - \omega_\text{initial}}{\alpha}[/tex]

    In the case of part (c) you want to know how long it takes for the fan to come to rest, i.e. the final angular velocity is zero. Hence,

    [tex]\Delta t = \frac{- \omega_\text{initial}}{\alpha}[/tex]

    Does that make sense?
     
  4. Apr 19, 2008 #3
    Ahh that makes crystal clear perfect sense. Thank you so much Hootenanny!!
     
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