Angular resolution using the Rayleigh criterion formula

[shanepitts]

Homework Statement

Homework Equations

θ=1.22 (λ/D)

The Attempt at a Solution

Just want to know if I properly answered this question.

Thanks in advance

 

[collinsmark]

Yes, your methodology is correct.

The only thing I can not confirm is how you are expected to choose the typical wavelengths involved. The GMRT is capable of operating on many frequencies in different bands -- altogether the range is greater than an order of magnitude from highest to lowest wavelength. Although yes, 1 m is within that range, if you're just looking for a ballpark figure.

Similarly, we can say the same thing about the optical wavelength (where 500 nm is typical), although it is a much narrower range (much less than 1 order of magnitude).

So anyway, I'm guessing that your approach is fine. Your usage of the formulae is good. I think your choices of wavelengths are good for ballpark figures, but I can't say for sure that you are supposed to be looking for ballpark figures.

 

[shanepitts]

Yes, your methodology is correct.

The only thing I can not confirm is how you are expected to choose the typical wavelengths involved. The GMRT is capable of operating on many frequencies in different bands -- altogether the range is greater than an order of magnitude from highest to lowest wavelength. Although yes, 1 m is within that range, if you're just looking for a ballpark figure.

Similarly, we can say the same thing about the optical wavelength (where 500 nm is typical), although it is a much narrower range (much less than 1 order of magnitude).

So anyway, I'm guessing that your approach is fine. Your usage of the formulae is good. I think your choices of wavelengths are good for ballpark figures, but I can't say for sure that you are supposed to be looking for ballpark figures.

Thank you for your detailed response

 

[paisiello2]

I think radio wavelengths larger than 10m are blocked by the atmosphere.