Angular Speed Homework: Car Brakes, Radii & Revs

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SUMMARY

The discussion focuses on a physics homework problem involving a car with an initial speed of 33.8 m/s that experiences a constant negative acceleration of 1.80 m/s² after braking. The solution calculates that each tire makes approximately 153.1 revolutions before the car stops, using the formula Δx = vo² / -2a. Additionally, it determines the angular speed of the wheels at half the total stopping distance to be 23.9 rad/s, confirming that the tangential velocity equals the angular velocity due to the absence of skidding.

PREREQUISITES
  • Understanding of kinematic equations, specifically v² = vo² + 2aΔx
  • Familiarity with angular motion concepts, including the relationship between linear and angular velocity
  • Knowledge of circular motion, particularly the circumference formula C = 2πr
  • Basic algebra skills for manipulating equations and solving for variables
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics problems
  • Learn about the relationship between linear and angular motion in detail
  • Explore the effects of friction on tire performance and vehicle dynamics
  • Investigate real-world applications of angular velocity in automotive engineering
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicle braking and tire performance.

mandy9008
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Homework Statement


A car initially traveling at 33.8 m/s undergoes a constant negative acceleration of magnitude 1.80 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car does not skid and the tires have radii of 0.330 m? (b) What is the angular speed of the wheels when the car has traveled half the total distance?


Homework Equations


v2 = vo2 + 2aΔx
C=2πr


The Attempt at a Solution


a. Δx = vo2 /-2a
Δx = 33.8 m/s 2 / (-2(-1.80 m/s2))
Δx = 317.3 m

# rev = 317.3 m / 2π (0.33m)
# rev = 153.1

b. v2 = 33.8 m/s2 + 2(-1.80 m/s2)(158.65m)
v = 23.9 m/s --> ω = 23.9 rad/s
 
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Everything is fine except the very last step. The tangential velocity of the wheel is related to the angular velocity via vT = rω. The reason you can assume that v = vT is because the wheels do not skid.
 

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