A 1000 kg car travelling rightward at 25 m/s slams on the breaks and skids to a stop (with locked wheels). Find the distance required to stop it. Coefficient of friction between the tires and the road is 0.95. Let g=9.8 m/s^2 Solution: 2aΔx=vf2- vo2 a=µg 2 µg Δx=vf2- vo2 vf=0 2 µg Δx=- vo2 Δx=- vo2/2 µg Δx=-252/(2×0.95×9.8) Δx=-33.6 m The answer became -33.6 m. Why is the value negative? The correct answer is 33.6. Thank you in advance!