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Angular tension on a hanging body

  • Thread starter MrJingles
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  • #1
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[SOLVED] Angular tension on a hanging body

Homework Statement




"In the diagram (see link), the tension on FT1 is 200N, angle measurements given are 50 deg and 30 deg left to right. What is the tension in FT2? What's the mass of the box?"

http://s175.photobucket.com/albums/w140/Sketchphonics/?action=view&current=Tensiondiagram.jpg
(^diagram of problem^)


The Attempt at a Solution



I've worked out the FT2 value by making 200cos50=FT2cos30; getting a final number of 148.445N (correct according to answer sheet).
Solving for the mass, I've added the two 'y direction forces' which should equal Fg times some mass. Thus, 200sin50+148.445sin30=9.8(M)

which comes out to M= 23.207 Kg. The answer on my worksheet is "15.4kg" so apparantly I've done something quite wrong. Any help would be much appreciated, thanks a bunch.
 

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Answers and Replies

  • #2
rl.bhat
Homework Helper
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Your answer seems to be correct.
 
  • #3
stewartcs
Science Advisor
2,177
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Your answer is correct. I got 23.207 Kg for the mass also so the book must be wrong.
 
  • #4
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I wasn't sure- every other time I've thought that I ended up being wrong.
Thanks anyways-

NJ
 

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