Angular Velocity and Acceleration graph

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SUMMARY

The discussion focuses on calculating angular displacement and angular acceleration using the provided equations. For angular displacement during the 4 seconds of motion, the area under the velocity-time graph is utilized. The angular acceleration from t=2 to t=4 is confirmed to be constant, with the correct application of the formula α = ω / t. Participants emphasize the importance of understanding the terms in the equations to avoid confusion in calculations.

PREREQUISITES
  • Understanding of angular displacement and acceleration concepts
  • Familiarity with kinematic equations for rotational motion
  • Ability to interpret velocity-time graphs
  • Knowledge of the relationship between angular velocity (ω) and angular acceleration (α)
NEXT STEPS
  • Study the derivation and application of kinematic equations for rotational motion
  • Learn how to calculate the area under a velocity-time graph to find displacement
  • Explore the relationship between linear and angular motion, particularly ω = v / r
  • Practice problems involving constant angular acceleration and its implications
USEFUL FOR

Students studying physics, particularly those focusing on rotational dynamics, as well as educators looking for examples of angular motion calculations.

df102015
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Homework Statement



04.EX32.jpg

A.) For the graph above what is the angular displacement during the 4 seconds of motion?
B.) For the graph above what is the angular acceleration from t=2 to t=4?

Homework Equations


α = at / r
α = ω / t
α = Θ / t^2
ω = Θ / t
ω = v / r
Θ = ω t + 0.5 α t^2

The Attempt at a Solution



A.) I used ω = Θ / t
rearranged it to ωt = Θ

but my issue is what ω do i use? 0, 10, 20? anything in between? And is this even the right equation to use?

B.) Isn't it not accelerating between t2 and t4? Or is it constant acceleration?
How i went about it is i used α = ω / t
since the time is 2 seconds, and the ω is 20. i got 10, but that was wrong :(
 
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There is an error in your image, unfortunately.
 
ProfuselyQuarky said:
There is an error in your image, unfortunately.
fixed it
 
For the first part it is the area under the graph.
For the second part the angular acceleration is constant.
 
df102015 said:
what ω do i use?
Do you know how to find the distance moved from a velocity-time graph?
df102015 said:
α = ω / t
Quoting formulae is of little use unless you know what the terms in the formulae represent. E.g. a=v/t is more informatively written as aavg=Δv/Δt. I.e. the average acceleration is the increase in velocity divided by the elapsed time.
kinemath said:
For the second part the angular acceleration is constant
True, but of the choice
df102015 said:
not accelerating between t2 and t4? Or is it constant acceleration?
that response could be misleading.
@df102015 , what do you look at on a velocity-time graph to deduce the acceleration?
 

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