ZD_zainy
- 3
- 0
Angular velocity of a rolling object
- Thread starter ZD_zainy
- Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
7 replies · 1K views
- 16,219
- 4,934
Hello @ZD_zainy , 
!
Please read the PF guidelines: we are not allowed to help if you don't show your own attempt. What does one see in the graphs ?
!Please read the PF guidelines: we are not allowed to help if you don't show your own attempt. What does one see in the graphs ?
- 42,946
- 10,550
It can help to consider extreme cases. What if the cylinder were already at the end of the slope when released?
ZD_zainy
- 3
- 0
How can I show my attempt which I made to find a graph?BvU said:Hello @ZD_zainy ,
Please read the PF guidelines: we are not allowed to help if you don't show your own attempt. What does one see in the graphs ?
ZD_zainy
- 3
- 0
Oh sorry . The question’s diagram itself shows how the cylinder is in the slopeharuspex said:
- 16,219
- 4,934
You write up what leads you to pick 1) and discuss the differences between 1) and 3). Where does it occur ?ZD_zainy said:
Personally, I think the increase in ##\omega## is exaggerated (it looks almost like a jump)
- 16,043
- 9,259
For the angular velocity to exhibit a sudden increase at the very end when it flies off the incline, there must be an increased torque acting on it. Remember that a rolling object rotates about the instantaneous point of contact. What happens when it reaches the edge just before contact is lost?
- 42,946
- 10,550
You miss my point.ZD_zainy said:
You are puzzled that the correct answer shows a sudden acceleration just as the cylinder reaches the end of the slope. The reason may become clear if you consider the cylinder released from rest when it is already touching the end of the slope.
Draw the diagram for that.