Angular Velocity of a satellite

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SUMMARY

The discussion centers on calculating the altitude of a satellite moving in a circular orbit around the Earth at a velocity of 6.6 km/s. The relevant gravitational formula used is GmM/r² = mv²/r, which simplifies to r = GM/v². The user initially calculated an incorrect radius of 916,025,899 km due to unit conversion errors. Correcting the units to standard SI units (meters) is essential for accurate results.

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notsam
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Homework Statement

A satellite moves in a circular orbit around
the Earth at a speed of 6.6 km/s.
Determine the satellite’s altitude above
the surface of the Earth. Assume the
Earth is a homogeneous sphere of radius
6370 km and mass 5.98 × 1024 kg. The
value of the universal gravitational constant
is 6.67259 × 10−11 N · m2/kg2.
Answer in units of km.



Homework Equations

m= mass of the satalite, M= mass of eart, G=gravitational constant, v= veolocity, r= radius of the entire orbit, and re= radius of the earth

The Attempt at a Solution

Ok so I start with GmM/r^2=mv^2/r, and then I simplify to r= GM/v^2, solving for r I get 916025899 km I then subtract the radius of the Earth "re" from it to get, 9160252629 km. This however is not the correct awnser. I can't figure what I am doing wrong I have already converted all of my units to km. I would REALLY REALLY appreciate step by step instructions on what I am doing wrong.
 
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notsam said:
Ok so I start with GmM/r^2=mv^2/r, and then I simplify to r= GM/v^2, solving for r I get 916025899 km
Did you use correct units? That equation assumes standard units: v in m/s, r in meters, etc.

Use standard units, then convert to whatever you want at the end.
 
You're a genius, I could'nt figure out what I was doing wrong thank you.
 
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