1. The problem statement, all variables and given/known data A solid disk is spinning around it center with an angular velocity of 35.0 rad/s. The disk has a mass of 3.6kg and a radius of .50m. You drop a thin ring with the same radius and a mass on the disk along the same center of rotation. What is the angular velocity of the disk and ring? 2. Relevant equations Id= 1/2mR^2 Ir=mR^2 w=vf/R 3. The attempt at a solution Id=1/2(3.6kg)(.50)^2 =.45 kg m/s Ir= (3.6)(.50)^2= .90 W= (I'd+Ir)/ R = (.45+.90)/(.50) =2.7 rad/s Is that the correct answer?