Angular velocity of ball-mass system

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SUMMARY

The discussion focuses on calculating the angular velocity of a ball-mass system after a bullet embeds itself in one of the balls. The system consists of four balls connected by low-mass rods, with specific parameters: bullet mass (m = 0.004 kg), bullet velocity (v = 450 m/s), and masses of the balls (M1 = 1.4 kg, M2 = 0.3 kg). The initial moment of inertia (Iinitial) is calculated using the formula I = (2/5)(2*[1.4*0.7^2]+2[0.3*0.2^2]). The key conclusion is that conservation of angular momentum, rather than conservation of mechanical energy, must be applied to find the final angular speed after the collision.

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smedearis
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Homework Statement


A device consisting of four heavy balls connected by low-mass rods is free to rotate about an axle. It is initially not spinning. A small bullet traveling very fast buries itself in one of the balls. In the diagram, m = 0.004 kg, v = 450 m/s, M1 = 1.4 kg, M2 = 0.3 kg, R1 = 0.7 m, and R2 = 0.2 m. The axle of the device is at the origin < 0, 0, 0 >, and the bullet strikes at location < 0.228, 0.662, 0 > m. Just after impact, what is the angular speed?

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Homework Equations


L=Iw
Iinitial=(2/5)(2*[1.4*0.7^2]+2[0.3*0.2^2])
Ifinal=(2/5)[1.404*0.7^2+1.4*0.7^2+2(0.3*0.2^2)]?
Delta E=Delta(.5*I*w^2)

The Attempt at a Solution


I tried to use conservation of energy, where the Final E=Initial E, and just solve for Wfinal.. but the answer was wrong. I feel like I'm missing something.
 
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In collisions where things stick together, mechanical energy is not conserved. You need conservation of angular momentum.
 

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