Angular velocity using Newton's law

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Homework Help Overview

The problem involves a small object of mass m placed on the inner surface of a rotating conical dish, requiring the calculation of minimum and maximum angular speeds (ω) to keep the object at rest. The context includes the application of Newton's laws in a non-inertial frame, with specific attention to forces acting on the object and their components along designated axes.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the object and the need to resolve these forces into components along different axes. There are attempts to clarify the application of Newton's second law in this context, particularly regarding the correct components of gravitational and centripetal forces.

Discussion Status

Some participants have provided guidance on drawing free body diagrams and resolving forces, while others express confusion about the direction of forces and the setup of equations. There is an ongoing exploration of the correct angles to use in the calculations, with some participants noting progress in understanding but still facing challenges in solving the equations.

Contextual Notes

Participants mention language barriers affecting comprehension of the physics concepts, and there are references to specific angles (30° and 60°) that are critical to the problem setup. The discussion reflects a collaborative effort to clarify these points without reaching a definitive solution.

Huumah
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Homework Statement



Small object of mass m is placed on the inner surface of the conical dish which can rotate with angular speed ω.

For μ=0.3 calculate the minumum and the maximum ω such that the object is remains at rest. Solve the problem using the indicated axes x-y.

Do the following steps:
(a) Show all forces acting on the object and and the acceleration
(b) Write Newton’s second law along both axes and solve.
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Homework Equations


F=ma=m*ω2*r

The Attempt at a Solution



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I have plugged in numbers and got answers for ωmax and ωmin but I don't get the right answer.
I have solved it right when I choose axis the ordinary X-Y axis but I need to know how to solve with using the other axis mentioned in the problem

The right answer is
ωmax=7.214 rad/s and ωmin =3.405 rad/s
 
Last edited:
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Your equation for both the X and Y direction is wrong.
You have taken the wrong component of mg and mω2r along the X direction. In the RHS, it won't be completely mω2r, it will be some component of this force. Make a free body diagram.
 
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In my free body diagram i have the fricton coefficient on both sides because it can go both upwards and downwards.

I don't really get what I should do on the right hand side for mω2*r

I have been trying for a few hours now and I am completely lost now.
 
Huumah said:
In my free body diagram i have the fricton coefficient on both sides because it can go both upwards and downwards.
Correct!
I don't really get what I should do on the right hand side for mω2*r
The force mω2r doesn't act in the X direction, so you will have to take its component along the X direction and solve.
See the image below, that should help you.
5bxqfc.png
 
Thanks very much.

I did not know in what direction the ω2 force was heading. Tried to read it in my physics book but english is not my first language so i didn't understand it.

I feel like I'm getting closer but there is something wrong in my 2 equations because I can't solve them ( because there is something wrong with them)

Can you give my a hint, Sir?
r5m4p.png
 
Huumah said:
I did not know in what direction the ω2 force was heading. Tried to read it in my physics book but english is not my first language so i didn't understand it.
ω2r is the centripetal acceleration. Don't think of mω2r as a force, but as mass*acceleration. (View things from the usual inertial frame.)

I feel like I'm getting closer but there is something wrong in my 2 equations because I can't solve them ( because there is something wrong with them)
Why can't you solve them? Eliminate N. (I think you have one of your angles wrong.)
 
I always got an error when i tried to solve it using wolfram alpha.

I just probably had a silly typo because it worked when I typed it in again.

I got it right when i changed the angle to 30° in the formula for y axis.

But I still don't get why it is not 60° in the y-axis formula.

Anyway thank you both so much for the help. Such a lovely community.
 
Huumah said:
I got it right when i changed the angle to 30° in the formula for y axis.

But I still don't get why it is not 60° in the y-axis formula.
The angle between mg and your y-axis is 30 degrees; the angle between mω2r and your y-axis is 60 degrees. And sin(30)=cos(60) & sin(60)=cos(30).
 

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