- #1

Like Tony Stark

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- Homework Statement
- The bodies shown in the picture spin on a horizontal plane, describing a circular path with constant acceleration. They're connected by ropes that resist ##1100 N## (each rope). Find the angular velocity when one of the ropes is cut.

- Relevant Equations
- Newton's equation

I wrote Newton's equations for each body (I took ##x## as the axis aligned with the tension)

##m_1##:

##x)f*_1 -T_1+T_2=0##

Where ##f*_1=\omega ^2 r_1##

##m_2##

##x)f*_2 -T_2=0##

##x)f*_2=T_2##

Where ##f*_2=\omega ^2 r_2##

I wrote that ##T_2=1100 N## and solved for ##\omega##, and I got ##\omega =20.56 \frac{rad}{s}##.

Then, I wrote ##T_2=f*_2## in the equation for ##m_1##, replace ##T_1=1100## and solved for ##\omega##. Doing so I found that ##\omega = 16.37 \frac{rad}{s}##.

So, the first rope will be cut with less angular velocity.

Is this right?

##m_1##:

##x)f*_1 -T_1+T_2=0##

Where ##f*_1=\omega ^2 r_1##

##m_2##

##x)f*_2 -T_2=0##

##x)f*_2=T_2##

Where ##f*_2=\omega ^2 r_2##

I wrote that ##T_2=1100 N## and solved for ##\omega##, and I got ##\omega =20.56 \frac{rad}{s}##.

Then, I wrote ##T_2=f*_2## in the equation for ##m_1##, replace ##T_1=1100## and solved for ##\omega##. Doing so I found that ##\omega = 16.37 \frac{rad}{s}##.

So, the first rope will be cut with less angular velocity.

Is this right?