Annihilation of electron and positron

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SUMMARY

The discussion centers on the annihilation of a positron with kinetic energy of 2.2 MeV colliding with an electron at rest, resulting in the production of gamma photons. The total energy calculated, including rest mass, is 3.222 MeV, derived from the equation (0.511 MeV x 2) + 2.2 MeV. To find the average energy of the two gamma photons produced, the total energy must be divided by two, yielding an average of 1.611 MeV per photon. This calculation resolves the initial confusion regarding the energy distribution in the annihilation process.

PREREQUISITES
  • Understanding of particle physics concepts, specifically electron and positron interactions.
  • Familiarity with energy calculations involving rest mass and kinetic energy.
  • Knowledge of gamma photon production in particle annihilation events.
  • Basic proficiency in using equations related to energy conservation in physics.
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  • Study the principles of particle-antiparticle annihilation in detail.
  • Learn about the properties and behavior of gamma photons produced in high-energy collisions.
  • Explore energy conservation laws in particle physics, focusing on relativistic effects.
  • Investigate real-world applications of positron emission tomography (PET) in medical imaging.
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ehabmozart
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Homework Statement


A positron with kinetic energy 2.2MeV collides with an electron at rest, and annihilate each other.
a. Calculate the average energy of the two gamma photons produced as a result of annihilation


Homework Equations





The Attempt at a Solution


I would infact calculate the energy in the left hand side including the rest masses.. isn't it.. So it would be (0.511 x 2) + 2.2 = 3.222 MeV .. But this doesn't seem the answer.. Any help guys?
 
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hi ehabmozart! :smile:
ehabmozart said:
A positron with kinetic energy 2.2MeV collides with an electron at rest, and annihilate each other.
a. Calculate the average energy of the two gamma photons produced as a result of annihilation

I would infact calculate the energy in the left hand side including the rest masses.. isn't it.. So it would be (0.511 x 2) + 2.2 = 3.222 MeV .. But this doesn't seem the answer.. Any help guys?

maybe they want you to divide by 2, for the average?
 
Thanks.. I guess this gave me the answer... Dude, i will owe u if u just solve the question in this link.. Drivin' me crazy and no replies till now
Here is the link "https://www.physicsforums.com/showthread.php?t=612956"
 

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